5x^2+x+10=14

Solution for 5x^2+x+10=14 equation:

5x^2+x+10=14

We move all terms to the left:

5x^2+x+10-(14)=0

We add all the numbers together, and all the variables

5x^2+x-4=0

a = 5; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·5·(-4)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-9}{2*5}=\frac{-10}{10}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+9}{2*5}=\frac{8}{10}
=4/5
$